Absorbance To Concentration Calculator
Work out absorbance to concentration instantly with clear inputs, formula shown and shareable results.
About Absorbance To Concentration Calculator
Reading a concentration off a spectrophotometer inverts Beer-Lambert: c = A/(epsilon x l). An absorbance of 0.75 in a 1 cm cell with molar absorptivity 15,000 corresponds to 5.0e-5 mol/L, or 50 micromolar. Accuracy is best between absorbance 0.1 and 1.0, so the calculator flags readings outside that band.
Formulas
Inverted Beer-Lambert
c = A / (epsilon x l)
Transmittance check
%T = 100 x 10^-A
Worked example
With the default values below, Absorbance To Concentration Calculator returns Concentration of 5.0000 × 10⁻⁵. Change any input above and every figure here is recalculated in your browser.
Inputs used
- Measured absorbanceminimum 0
- 0.75
- Molar absorptivityminimum 0 L/(mol cm)
- 15,000 L/(mol cm)
- Cuvette path lengthminimum 0 cm
- 1 cm
Results
- Concentration
- 5.0000 × 10⁻⁵ mol/L
- Same Concentration In Micromolar
- 50.000
- Percent Transmittance
- 17.78%
- Measurement Quality
- Within the reliable 0.1-1.0 absorbance window
Step by step
- 1Values used
- 2Inverted Beer-Lambert
- 3Transmittance check
- 4Concentration= 0.0001 mol/L
- 5Same Concentration In Micromolar= 50.000
- 6Percent Transmittance= 17.78
- 7Measurement Quality= Within the reliable 0.1-1.0 absorbance window
Assumptions and limits
- The result is derived only from the 3 inputs listed above. Anything not among them is not part of the calculation.
- In particular, this calculator does not take inflation, tax, fees or charges or compounding frequency into account.
- Figures are rounded for display to 4 decimal places, so totals built from several rounded parts can differ slightly from the unrounded arithmetic.
How these calculators are built and tested is described on the Methodology page. If a figure looks wrong, please report it.
Frequently Asked Questions
What if I do not know the molar absorptivity?
Build a calibration line from standards instead: the slope is epsilon times the path length, so the unknown reads straight off the graph.
Does a longer cuvette help with dilute samples?
Yes. A 10 cm cell multiplies absorbance tenfold, which is a standard trick for trace analysis.
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