Changeover Time Calculator
Work out changeover time instantly with clear inputs, formula shown and shareable results.
About Changeover Time Calculator
Only internal elements plus adjustment stop the machine, so those alone are the downtime that matters. External work — staging tooling, pre-heating, paperwork — should be moved outside the stop. Where several operators can work simultaneously, downtime approaches the work content divided by crew size.
Formulas
Changeover time
Machine downtime = internal elements + adjustment; total work content = internal + external + adjustment
Parallel working
Best-case downtime = downtime / operators
Worked example
With the default values below, Changeover Time Calculator returns Machine Downtime of 65.00. Change any input above and every figure here is recalculated in your browser.
Inputs used
- Internal Elements (machine stopped)minimum 0 minutes
- 45 minutes
- External Elements (machine running)minimum 0 minutes
- 30 minutes
- Adjustment And First-Off Approvalminimum 0 minutes
- 20 minutes
- Operators On Changeoverminimum 1
- 2
Results
- Machine Downtime
- 65.00
- Total Changeover Work Content
- 95.00
- Labour Minutes Consumed
- 130.00
- Downtime If Fully Parallelised
- 32.50
Step by step
- 1Values used
- 2Changeover time
- 3Parallel working
- 4Machine Downtime= 65.00
- 5Total Changeover Work Content= 95.00
- 6Labour Minutes Consumed= 130.00
- 7Downtime If Fully Parallelised= 32.50
Assumptions and limits
- The result is derived only from the 4 inputs listed above. Anything not among them is not part of the calculation.
- In particular, this calculator does not take inflation, tax, fees or charges or compounding frequency into account.
- Figures are rounded for display to 2 decimal places, so totals built from several rounded parts can differ slightly from the unrounded arithmetic.
How these calculators are built and tested is described on the Methodology page. If a figure looks wrong, please report it.
Frequently Asked Questions
Why is adjustment counted with internal time?
Trial-and-error adjustment happens with the machine stopped and often exceeds the mechanical changeover itself. Replacing adjustment with positive stops and settings is the largest single SMED gain.
Is more operators always faster?
Only up to the point where they interfere with each other or run out of parallel tasks. Two or three is usually optimal on a single machine.
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