Work out circle through three points instantly with clear inputs, formula shown and shareable results.
Three non-collinear points determine exactly one circle. Its centre is the common intersection of the perpendicular bisectors, obtained in closed form from the determinant of the squared coordinates.
Circumcentre
D = 2[xA(yB−yC) + xB(yC−yA) + xC(yA−yB)], then Ux and Uy from the squared-length sums
This is a right triangle, so the centre is the hypotenuse midpoint (3, 4) and the radius is 5.
The determinant D is zero and no finite circle exists; the 'circle' degenerates to a straight line.