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To undo a logarithm, exponentiate both sides. From k·log_b(x) = c divide by k and then raise b to that power, giving x = b^(c/k).
Log equation
k·log_b(x) = c ⇒ x = b^(c/k)
x = 3⁴ = 81.
Yes when the original equation has sums of logs, because the algebra can introduce values that make an argument non-positive.