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In base ten each position is worth ten times the one to its right, so the digit in position p (counting from the units as 1) contributes digit × 10^(p−1).
Place value
value = digit × 10^(position − 1)
The digit is 2 in the hundreds place, so its place value is 200.
No. The face value of that 2 is just 2; its place value is 200.