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Calcrivo

CRAC Capacity Calculator

Size CRAC/CRAH cooling capacity in tons of refrigeration from IT heat load, with a safety margin and room heat-gain allowance.

Inputs

kW

IT equipment power draw ≈ heat generated (nearly all electrical power becomes heat)

Lighting, people, envelope/solar gain, and other non-IT heat sources

Margin for future growth and to avoid running cooling at 100% of calculated need

Recommended Cooling Capacity

37.53tons

Calculated Requirement (no safety margin)

31.28tons

Total Heat Load (IT + room gain)

110.00kW

Total Heat Load

375,335BTU/hr

Step by step

  1. Values used

    IT Heat Load = 100 kW; Additional Room Heat Gain = 10; Safety Factor = 20

  2. Required cooling capacity

    tons = (IT_heat_kW × (1 + room_loss%)) / 3.517, then apply safety factor

  3. Recommended Cooling Capacity

    = 37.53 tons

  4. Calculated Requirement (no safety margin)

    = 31.28 tons

  5. Total Heat Load (IT + room gain)

    = 110.00 kW

  6. Total Heat Load

    = 375,335 BTU/hr

How it works

CRAC/CRAH cooling capacity is sized from the total heat that must be removed from the room, not just the IT load: nearly all electrical power consumed by IT equipment converts to heat, and additional heat comes from lighting, personnel, and building envelope gain. One ton of refrigeration equals 3.517 kW of heat-removal capacity, so dividing total heat load by 3.517 gives the required tonnage, and a safety factor is added on top to cover future load growth and avoid running cooling units at their absolute limit.

Formula

Required cooling capacity

tons = (IT_heat_kW × (1 + room_loss%)) / 3.517, then apply safety factor

P_{IT}
IT equipment heat load in kW
r
Room heat gain fraction
s
Safety factor fraction

Frequently Asked Questions

Why does IT power draw equal heat load?

By the first law of thermodynamics, essentially all electrical energy consumed by IT equipment (CPUs, power supplies, fans, drives) is converted to heat with nowhere else for the energy to go — so a server drawing 500W of power load also generates approximately 500W of heat that the cooling system must remove.

What is a 'ton' of cooling capacity?

One ton of refrigeration is defined as the heat-removal rate needed to melt one ton of ice in 24 hours, equal to 3.517 kW (or 12,000 BTU/hr) of continuous heat removal — it's a legacy unit still standard in HVAC and data center cooling sizing.

Why add a safety factor on top of the calculated tonnage?

Running cooling units at exactly their calculated maximum leaves no margin for equipment additions, hot-spot variability, or degraded performance as filters and coils age — a 15-25% safety factor is standard practice to keep the system comfortably under its rated limit during normal operation.

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