Work out pcb trace width instantly with clear inputs, formula shown and shareable results.
IPC-2221 gives cross-sectional area from current and temperature rise: A = (I / (k x dT^0.44))^(1/0.725), with k = 0.048 for external traces and 0.024 for internal ones. Dividing by copper thickness gives the width, which is why 1 oz copper needs roughly 1 mm per 3 A for a 20 degree rise.
IPC-2221 trace width
A(mil^2) = (I / (k x dT^0.44))^(1/0.725); width = A / copper thickness
Electrical results are planning estimates only. Verify against the applicable wiring rules (IEC 60364, BS 7671, NEC or local code) and have all installation work designed and checked by a qualified electrician.
They have no convective or radiative cooling path, only conduction through the laminate, so they need twice the area for the same rise.
No. Voltage drop along a long trace and the current-handling of vias and connectors often govern before the trace itself does.