Work out hydrogen spectrum (rydberg) instantly with clear inputs, formula shown and shareable results.
The Rydberg formula gives 1/lambda = R(1/n1^2 - 1/n2^2), using the hydrogen value R = 1.09678e7 per metre. The 3 to 2 transition yields 656.5 nm - the red H-alpha line that dominates emission nebulae. Transitions ending at n = 1 land in the ultraviolet Lyman series, at n = 2 in the visible Balmer series.
Rydberg formula
1 / lambda = R(H) (1/n1^2 - 1/n2^2), R(H) = 1.09678e7 /m
Photon energy
E = h c / lambda
The 3 to 2 Balmer transition at 656.3 nm. It is the strongest visible hydrogen line and gives nebulae their red colour.
Because dropping to n = 1 releases at least 10.2 eV, which corresponds to 121.6 nm - deep ultraviolet, absorbed by the atmosphere.