Work out maximum height of projectile instantly with clear inputs, formula shown and shareable results.
Only the vertical component of the launch velocity fights gravity, so the peak height is (v sin theta)^2 divided by 2g. At the apex the vertical velocity is zero but the horizontal component is untouched, which is why the projectile is still moving there. Launching at 20 m/s and 60 degrees peaks at 15.3 m after 1.77 s.
Maximum height
H = (v sin theta)^2 / (2g)
Time to apex
t = v sin theta / g
No, only the vertical part is. The horizontal component v cos theta carries on unchanged, so the projectile is at its slowest but not stationary.
Straight up, 90 degrees. Height depends on sin theta while range depends on sin 2theta, which is why they peak at different angles.