Skip to content
ENExplore Calculators

Playoff Probability Calculator

Work out playoff probability instantly with clear inputs, formula shown and shareable results.

About Playoff Probability Calculator

Assuming each remaining game is independent, the chance of getting enough wins is the binomial tail: the sum of C(games, k) p^k (1-p)^(games-k) for every k at or above the wins needed. The binomial tail is far more informative than the average, because a team needing seven wins from ten at 45% each has a real but small chance rather than none.

Formulas

Wins needed

wins needed = ceiling((target points - current points) / 3)

Binomial tail

P = sum over k >= wins needed of C(n, k) p^k (1 - p)^(n - k)

Worked example

With the default values below, Playoff Probability Calculator returns Chance of reaching the target of 26.16%. Change any input above and every figure here is recalculated in your browser.

Inputs used

Points so farminimum 0
40
Games remainingaccepts 1–30
10
Points needed to qualifyminimum 1
58
Chance of winning each remaining gameaccepts 1–99 %
45 %

Results

Chance of reaching the target
26.16%
Wins needed
6
Wins expected
4.50
Expected final points
53.5

Step by step

  1. 1Values used
  2. 2Wins needed
  3. 3Binomial tail
  4. 4Chance of reaching the target= 26.16
  5. 5Wins needed= 6
  6. 6Wins expected= 4.50
  7. 7Expected final points= 53.5

Assumptions and limits

  • The result is derived only from the 4 inputs listed above. Anything not among them is not part of the calculation.
  • In particular, this calculator does not take inflation, tax, fees or charges or compounding frequency into account.
  • Figures are rounded for display to 2 decimal places, so totals built from several rounded parts can differ slightly from the unrounded arithmetic.

How these calculators are built and tested is described on the Methodology page. If a figure looks wrong, please report it.

Frequently Asked Questions

How is the Playoff Probability figure worked out?

wins needed = ceiling((target points - current points) / 3). Assuming each remaining game is independent, the chance of getting enough wins is the binomial tail: the sum of C(games, k) p^k (1-p)^(games-k) for every k at or above the wins needed.

Why does this matter?

The binomial tail is far more informative than the average, because a team needing seven wins from ten at 45% each has a real but small chance rather than none.

What do I need to enter?

Enter points so far, games remaining, points needed to qualify, chance of winning each remaining game. The defaults shown are a realistic worked example — swap in your own figures to get a result you can use.

Related Calculators

Playoff Probability Calculator | Calcrivo