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Sound level is logarithmic, so it cannot be converted by a multiplication factor. Pressure uses 20 log10(p/20 uPa) and intensity 10 log10(I/1e-12), which is why 80 dB corresponds to 0.2 Pa and 1e-4 W/m2. The two references are chosen to agree numerically for a plane wave in air.
Pressure level
L = 20 log10(p / 20e-6 Pa)
Intensity level
L = 10 log10(I / 1e-12 W/m2)
Because intensity is proportional to pressure squared, and squaring inside a logarithm becomes a factor of two outside it.
No. Two 80 dB sources give 83 dB, not 160, because the underlying intensities add rather than the levels.